Measurements in growth were made on samples that were each given one of three treatments. Rather than assuming a data distribution and testing the equality of population means with one-way ANOVA, you decide to select the Kruskal-Wallis procedure to test H0: h1 = h2 = h3, versus H1: not all h's are equal, where the h's are the population medians.
1 Open the worksheet EXH_STAT.MTW.
2 Choose Stat > Nonparametrics > Kruskal-Wallis.
3 In Response, enter Growth.
4 In Factor, enter Treatment. Click OK.
Session window output
Kruskal-Wallis Test: Growth versus Treatment
Kruskal-Wallis Test on Growth
Treatment N Median Ave Rank Z 1 5 13.20 7.7 -0.45 2 5 12.90 4.3 -2.38 3 6 15.60 12.7 2.71 Overall 16 8.5
H = 8.63 DF = 2 P = 0.013 H = 8.64 DF = 2 P = 0.013 (adjusted for ties) |
The sample medians for the three treatments were calculated 13.2, 12.9, and 15.6. The z-value for level 1 is -0.45, the smallest absolute z-value. This size indicates that the mean rank for treatment 1 differed least from the mean rank for all observations. The mean rank for treatment 2 was lower than the mean rank for all observations, as the z-value is negative (z = -2.38). The mean rank for treatment 3 is higher than the mean rank for all observations, as the z-value is positive (z = 2.71).
The test statistic (H) had a p-value of 0.013, both unadjusted and adjusted for ties, indicating that the null hypothesis can be rejected at a levels higher than 0.013 in favor of the alternative hypothesis of at least one difference among the treatment groups.